Optimal. Leaf size=179 \[ -\frac{a^2 (A-B)}{32 d (a \sin (c+d x)+a)^4}+\frac{5 A+3 B}{64 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 A+B}{32 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{5 (3 A+B) \tanh ^{-1}(\sin (c+d x))}{64 a^2 d}-\frac{a (3 A-B)}{48 d (a \sin (c+d x)+a)^3}+\frac{A+B}{64 d (a-a \sin (c+d x))^2}-\frac{3 A}{32 d (a \sin (c+d x)+a)^2} \]
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Rubi [A] time = 0.205736, antiderivative size = 179, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {2836, 77, 206} \[ -\frac{a^2 (A-B)}{32 d (a \sin (c+d x)+a)^4}+\frac{5 A+3 B}{64 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 A+B}{32 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{5 (3 A+B) \tanh ^{-1}(\sin (c+d x))}{64 a^2 d}-\frac{a (3 A-B)}{48 d (a \sin (c+d x)+a)^3}+\frac{A+B}{64 d (a-a \sin (c+d x))^2}-\frac{3 A}{32 d (a \sin (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 77
Rule 206
Rubi steps
\begin{align*} \int \frac{\sec ^5(c+d x) (A+B \sin (c+d x))}{(a+a \sin (c+d x))^2} \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{A+\frac{B x}{a}}{(a-x)^3 (a+x)^5} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^5 \operatorname{Subst}\left (\int \left (\frac{A+B}{32 a^5 (a-x)^3}+\frac{5 A+3 B}{64 a^6 (a-x)^2}+\frac{A-B}{8 a^3 (a+x)^5}+\frac{3 A-B}{16 a^4 (a+x)^4}+\frac{3 A}{16 a^5 (a+x)^3}+\frac{5 A+B}{32 a^6 (a+x)^2}+\frac{5 (3 A+B)}{64 a^6 \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{A+B}{64 d (a-a \sin (c+d x))^2}-\frac{a^2 (A-B)}{32 d (a+a \sin (c+d x))^4}-\frac{a (3 A-B)}{48 d (a+a \sin (c+d x))^3}-\frac{3 A}{32 d (a+a \sin (c+d x))^2}+\frac{5 A+3 B}{64 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 A+B}{32 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac{(5 (3 A+B)) \operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{64 a d}\\ &=\frac{5 (3 A+B) \tanh ^{-1}(\sin (c+d x))}{64 a^2 d}+\frac{A+B}{64 d (a-a \sin (c+d x))^2}-\frac{a^2 (A-B)}{32 d (a+a \sin (c+d x))^4}-\frac{a (3 A-B)}{48 d (a+a \sin (c+d x))^3}-\frac{3 A}{32 d (a+a \sin (c+d x))^2}+\frac{5 A+3 B}{64 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 A+B}{32 d \left (a^2+a^2 \sin (c+d x)\right )}\\ \end{align*}
Mathematica [A] time = 0.664118, size = 123, normalized size = 0.69 \[ \frac{-\frac{3 (5 A+3 B)}{\sin (c+d x)-1}-\frac{6 (5 A+B)}{\sin (c+d x)+1}+\frac{3 (A+B)}{(\sin (c+d x)-1)^2}+\frac{4 (B-3 A)}{(\sin (c+d x)+1)^3}-\frac{6 (A-B)}{(\sin (c+d x)+1)^4}+15 (3 A+B) \tanh ^{-1}(\sin (c+d x))-\frac{18 A}{(\sin (c+d x)+1)^2}}{192 a^2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.135, size = 283, normalized size = 1.6 \begin{align*} -{\frac{15\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) A}{128\,d{a}^{2}}}-{\frac{5\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) B}{128\,d{a}^{2}}}+{\frac{A}{64\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}+{\frac{B}{64\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{5\,A}{64\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{3\,B}{64\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{3\,A}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{A}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{B}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{A}{16\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{B}{48\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{5\,A}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) }}-{\frac{B}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) }}+{\frac{15\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) A}{128\,d{a}^{2}}}+{\frac{5\,B\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{128\,d{a}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.05767, size = 279, normalized size = 1.56 \begin{align*} -\frac{\frac{2 \,{\left (15 \,{\left (3 \, A + B\right )} \sin \left (d x + c\right )^{5} + 30 \,{\left (3 \, A + B\right )} \sin \left (d x + c\right )^{4} - 10 \,{\left (3 \, A + B\right )} \sin \left (d x + c\right )^{3} - 50 \,{\left (3 \, A + B\right )} \sin \left (d x + c\right )^{2} - 17 \,{\left (3 \, A + B\right )} \sin \left (d x + c\right ) + 48 \, A - 16 \, B\right )}}{a^{2} \sin \left (d x + c\right )^{6} + 2 \, a^{2} \sin \left (d x + c\right )^{5} - a^{2} \sin \left (d x + c\right )^{4} - 4 \, a^{2} \sin \left (d x + c\right )^{3} - a^{2} \sin \left (d x + c\right )^{2} + 2 \, a^{2} \sin \left (d x + c\right ) + a^{2}} - \frac{15 \,{\left (3 \, A + B\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a^{2}} + \frac{15 \,{\left (3 \, A + B\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a^{2}}}{384 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.65888, size = 687, normalized size = 3.84 \begin{align*} \frac{60 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4} - 20 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2} + 15 \,{\left ({\left (3 \, A + B\right )} \cos \left (d x + c\right )^{6} - 2 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4} \sin \left (d x + c\right ) - 2 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \,{\left ({\left (3 \, A + B\right )} \cos \left (d x + c\right )^{6} - 2 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4} \sin \left (d x + c\right ) - 2 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (15 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{4} - 20 \,{\left (3 \, A + B\right )} \cos \left (d x + c\right )^{2} - 36 \, A - 12 \, B\right )} \sin \left (d x + c\right ) - 24 \, A - 72 \, B}{384 \,{\left (a^{2} d \cos \left (d x + c\right )^{6} - 2 \, a^{2} d \cos \left (d x + c\right )^{4} \sin \left (d x + c\right ) - 2 \, a^{2} d \cos \left (d x + c\right )^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.44561, size = 289, normalized size = 1.61 \begin{align*} \frac{\frac{60 \,{\left (3 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a^{2}} - \frac{60 \,{\left (3 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a^{2}} + \frac{6 \,{\left (45 \, A \sin \left (d x + c\right )^{2} + 15 \, B \sin \left (d x + c\right )^{2} - 110 \, A \sin \left (d x + c\right ) - 42 \, B \sin \left (d x + c\right ) + 69 \, A + 31 \, B\right )}}{a^{2}{\left (\sin \left (d x + c\right ) - 1\right )}^{2}} - \frac{375 \, A \sin \left (d x + c\right )^{4} + 125 \, B \sin \left (d x + c\right )^{4} + 1740 \, A \sin \left (d x + c\right )^{3} + 548 \, B \sin \left (d x + c\right )^{3} + 3114 \, A \sin \left (d x + c\right )^{2} + 894 \, B \sin \left (d x + c\right )^{2} + 2604 \, A \sin \left (d x + c\right ) + 612 \, B \sin \left (d x + c\right ) + 903 \, A + 93 \, B}{a^{2}{\left (\sin \left (d x + c\right ) + 1\right )}^{4}}}{1536 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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